To assess the extent of spread of visually construct the diagram: Next, consider the results of joint tests of memory and the cache of the same Sandra. For B120 4598/11, 3 and 4396 / 12 for 2200, 8 (here the first number – the average bandwidth in megabytes per second, depending on the size of blocks of transmitted information, the second number – the average logarithmic rate, the analog of the first value, but received in another way and expressed in fact, parrots, whose dimension is known only to developers, Sandra. The coefficient has the opposite value, ie the smaller the better). Read additional details here: Harold Ford, Memphis TN. The difference was: 4598/4396 * 100-100 = 4.6% and 12.8 / 11.3 * 100-100 = 13.3%. Here we first encounter with the strong scatter in test results, and in fact one and the same test.
Our task, however, do not score and the best selection and most reliable programs to test, so just accept the result as given, and the results of our tests will try to comment on if this will be arguments. I would also like to see that the average score difference in memory performance on this test (13.3 4.6) / 2 = 8.95 already much more similar to our previous results of 7.4 and 8.2 while still misses the 5% range of measurement error, the developers assure Sandra. Our chart this test: The next test tool perform well-known program 3DMark. We used a version of a 2003 3DMark03 because in more recent versions of the test result in parrots has smaller dimension than in this release and further comparative test desktop systems 3DMark05, for example, simply refused to work due to the inability to meet its sverhtrebovatelnye tests on older systems.